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<rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:media="http://search.yahoo.com/mrss/" version="2.0"><channel><title>halo</title><link>http://localhost:18090</link><atom:link href="http://localhost:18090/rss.xml" rel="self" type="application/rss+xml"/><description>halo</description><generator>Halo v2.22.14</generator><language>zh-cn</language><lastBuildDate>Mon, 4 May 2026 19:18:49 GMT</lastBuildDate><item><title><![CDATA[Object::isNull踩坑]]></title><link>http://localhost:18090/archives/object-isnullcai-keng</link><description><![CDATA[<img src="http://localhost:18090/plugins/feed/assets/telemetry.gif?title=Object%3A%3AisNull%E8%B8%A9%E5%9D%91&amp;url=/archives/object-isnullcai-keng" width="1" height="1" alt="" style="opacity:0;">如果数据库中查询出来的数据有一条为空的话 Object::isNull就为null 有两种解决办法: 1.修改sql语句 新增and ~.id IS NOT NULL这样查询出来的语句就排除了空值 2.删掉Object::isNull这个判断 改用isEmpty和!=null]]></description><guid isPermaLink="false">/archives/object-isnullcai-keng</guid><dc:creator>Administrator</dc:creator><pubDate>Thu, 23 Apr 2026 14:44:39 GMT</pubDate></item><item><title><![CDATA[Mycat核心概念]]></title><link>http://localhost:18090/archives/mycathe-xin-gai-nian</link><description><![CDATA[<img src="http://localhost:18090/plugins/feed/assets/telemetry.gif?title=Mycat%E6%A0%B8%E5%BF%83%E6%A6%82%E5%BF%B5&amp;url=/archives/mycathe-xin-gai-nian" width="1" height="1" alt="" style="opacity:0;">这张图展示的是典型的数据库中间件分片架构（常见于 MyCat 等系统），它清晰地描绘了数据从“逻辑概念”到“物理存储”的完整映射过程。 你可以把这个流程看作是一个快递分拣系统，以下是各个组件的具体含义和它们之间的关系： 1. 核心组件解析 逻辑库与逻辑表 (左侧) 含义：这是给应用程序（程序员）看到]]></description><guid isPermaLink="false">/archives/mycathe-xin-gai-nian</guid><dc:creator>Administrator</dc:creator><pubDate>Mon, 13 Apr 2026 14:13:29 GMT</pubDate></item><item><title><![CDATA[redis企业级实战]]></title><link>http://localhost:18090/archives/redisshi-zhan</link><description><![CDATA[<img src="http://localhost:18090/plugins/feed/assets/telemetry.gif?title=redis%E4%BC%81%E4%B8%9A%E7%BA%A7%E5%AE%9E%E6%88%98&amp;url=/archives/redisshi-zhan" width="1" height="1" alt="" style="opacity:0;">Redis企业实战面试题 - 含解析 一、基础概念篇 1.1 什么是Redis？它有哪些特点？ 答案： Re]]></description><guid isPermaLink="false">/archives/redisshi-zhan</guid><dc:creator>Administrator</dc:creator><pubDate>Tue, 31 Mar 2026 14:49:19 GMT</pubDate></item><item><title><![CDATA[jvm调优]]></title><link>http://localhost:18090/archives/jvmdiao-you</link><description><![CDATA[<img src="http://localhost:18090/plugins/feed/assets/telemetry.gif?title=jvm%E8%B0%83%E4%BC%98&amp;url=/archives/jvmdiao-you" width="1" height="1" alt="" style="opacity:0;">JVM企业级面试宝典 一、内存模型与垃圾回收 1.1 JVM内存结构 核心知识点： 堆内存（Heap） ：存储对象实例，分为新生代和老年代]]></description><guid isPermaLink="false">/archives/jvmdiao-you</guid><dc:creator>Administrator</dc:creator><category>默认分类</category><pubDate>Tue, 31 Mar 2026 14:37:52 GMT</pubDate></item></channel></rss>